What are the solutions to the equation (x+5)^2-200=25 ?

The solutions to the equation (x+5)^2-200=25 are x=10,x=-20

Find the zeros of (x+5)^2-200=25

The zeros of (x+5)^2-200=25 are x=10,x=-20

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(x + 5)^{2} - 200 = 25

x = 10, x = - 20

Solution steps

(x + 5)^{2} - 200 = 25

Move

200

to the right side

(x + 5)^{2} = 225

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 225 : x = 10

Solve

x + 5 = - 225 : x = - 20

The solutions to the quadratic equation are:

x = 10, x = - 20

t^{2} = 4 t - 4

x^{2} - x - 3 = 0

3 x^{2} - 18 = 2 x + 1

m^{2} + 12 m + 20 = 0

- 3 x^{2} - 120 = 0

What are the solutions to the equation (x+5)^2-200=25 ?
The solutions to the equation (x+5)^2-200=25 are x=10,x=-20
Find the zeros of (x+5)^2-200=25
The zeros of (x+5)^2-200=25 are x=10,x=-20