What are the solutions to the equation 2x^2+10x-1092=0 ?

The solutions to the equation 2x^2+10x-1092=0 are x=21,x=-26

Find the zeros of 2x^2+10x-1092=0

The zeros of 2x^2+10x-1092=0 are x=21,x=-26

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2 x^{2} + 10 x - 1092 = 0

x = 21, x = - 26

Solution steps

2 x^{2} + 10 x - 1092 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 1092 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 1092) = 94

x_{1, 2} = \frac{- 10 \pm 94}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 94}{2 \cdot 2}, x_{2} = \frac{- 10 - 94}{2 \cdot 2}

x = \frac{- 10 + 94}{2 \cdot 2} : 21

x = \frac{- 10 - 94}{2 \cdot 2} : - 26

The solutions to the quadratic equation are:

x = 21, x = - 26

x^{2} - 31 x - 180 = 0

(x + 6)^{2} - 49 = 0

(x) = 2 x^{2} - 7 x - 4

3 y^{2} + 16 y + 5 = 0

2 x^{2} - 8 = - 8

What are the solutions to the equation 2x^2+10x-1092=0 ?
The solutions to the equation 2x^2+10x-1092=0 are x=21,x=-26
Find the zeros of 2x^2+10x-1092=0
The zeros of 2x^2+10x-1092=0 are x=21,x=-26