What are the solutions to the equation -3=4(x)^2-(x)-3 ?

The solutions to the equation -3=4(x)^2-(x)-3 are x= 1/4 ,x=0

Find the zeros of -3=4(x)^2-(x)-3

The zeros of -3=4(x)^2-(x)-3 are x= 1/4 ,x=0

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- 3 = 4 (x)^{2} - (x) - 3

x = \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = 0

Solution steps

- 3 = 4 x^{2} - (x) - 3

Refine

- 3 = 4 x^{2} - x - 3

Switch sides

4 x^{2} - x - 3 = - 3

Move

3

to the left side

4 x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 4}

x = \frac{- ( - 1 ) + 1}{2 \cdot 4} : \frac{1}{4}

x = \frac{- ( - 1 ) - 1}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

(c - 3)^{2} = 100

V, q = \frac{1}{2} p V^{2}

4 - x^{2} + 3 x = 0

12 x^{2} + 144 = 640

x^{2} + 40 x + 200 = 0

What are the solutions to the equation -3=4(x)^2-(x)-3 ?
The solutions to the equation -3=4(x)^2-(x)-3 are x= 1/4 ,x=0
Find the zeros of -3=4(x)^2-(x)-3
The zeros of -3=4(x)^2-(x)-3 are x= 1/4 ,x=0