What are the solutions to the equation -2x^2-20x-146=0 ?

The solutions to the equation -2x^2-20x-146=0 are x=-5-4sqrt(3)i,x=-5+4sqrt(3)i

Find the zeros of -2x^2-20x-146=0

The zeros of -2x^2-20x-146=0 are x=-5-4sqrt(3)i,x=-5+4sqrt(3)i

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- 2 x^{2} - 20 x - 146 = 0

x = - 5 - 43 i, x = - 5 + 43 i

Solution steps

- 2 x^{2} - 20 x - 146 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 2 ) ( - 146 )}{2 ( - 2 )}

Simplify

(- 20)^{2} - 4 (- 2) (- 146) : 163 i

x_{1, 2} = \frac{- ( - 20 ) \pm 16 3 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 16 3 i}{2 ( - 2 )}, x_{2} = \frac{- ( - 20 ) - 16 3 i}{2 ( - 2 )}

x = \frac{- ( - 20 ) + 16 3 i}{2 ( - 2 )} : - 5 - 43 i

x = \frac{- ( - 20 ) - 16 3 i}{2 ( - 2 )} : - 5 + 43 i

The solutions to the quadratic equation are:

x = - 5 - 43 i, x = - 5 + 43 i

4 (x - 1)^{2} = 4, (x - 1) 2 = 3636

\frac{x ( x - 3 )}{2} = 28

0.02 a^{2} - 0.02 a - 0.01 = 0

(3 x - 4) (x + 2) = 8

3 t^{2} - 3 t - 5 = 0

What are the solutions to the equation -2x^2-20x-146=0 ?
The solutions to the equation -2x^2-20x-146=0 are x=-5-4sqrt(3)i,x=-5+4sqrt(3)i
Find the zeros of -2x^2-20x-146=0
The zeros of -2x^2-20x-146=0 are x=-5-4sqrt(3)i,x=-5+4sqrt(3)i