What are the solutions to the equation -8x^2-157x+60=0 ?

The solutions to the equation -8x^2-157x+60=0 are x=-20,x= 3/8

Find the zeros of -8x^2-157x+60=0

The zeros of -8x^2-157x+60=0 are x=-20,x= 3/8

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- 8 x^{2} - 157 x + 60 = 0

x = - 20, x = \frac{3}{8}

Decimal Notation

x = - 20, x = 0.375

Solution steps

- 8 x^{2} - 157 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 157 ) \pm ( - 157 ) ^{2} - 4 ( - 8 ) \cdot 60}{2 ( - 8 )}

(- 157)^{2} - 4 (- 8) \cdot 60 = 163

x_{1, 2} = \frac{- ( - 157 ) \pm 163}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- ( - 157 ) + 163}{2 ( - 8 )}, x_{2} = \frac{- ( - 157 ) - 163}{2 ( - 8 )}

x = \frac{- ( - 157 ) + 163}{2 ( - 8 )} : - 20

x = \frac{- ( - 157 ) - 163}{2 ( - 8 )} : \frac{3}{8}

The solutions to the quadratic equation are:

x = - 20, x = \frac{3}{8}

x^{2} + 8 = - 3 x

x^{2} + 26 x = - 178

z^{2} + z^{2} = 9^{2}

6 x = 16 - x^{2}

(2 x - 7)^{2} = 81

What are the solutions to the equation -8x^2-157x+60=0 ?
The solutions to the equation -8x^2-157x+60=0 are x=-20,x= 3/8
Find the zeros of -8x^2-157x+60=0
The zeros of -8x^2-157x+60=0 are x=-20,x= 3/8