What are the solutions to the equation x^2+26x=-178 ?

The solutions to the equation x^2+26x=-178 are x=-13+3i,x=-13-3i

Find the zeros of x^2+26x=-178

The zeros of x^2+26x=-178 are x=-13+3i,x=-13-3i

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x^{2} + 26 x = - 178

x = - 13 + 3 i, x = - 13 - 3 i

Solution steps

x^{2} + 26 x = - 178

Move

178

to the left side

x^{2} + 26 x + 178 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 1 \cdot 178}{2 \cdot 1}

Simplify

2 6^{2} - 4 \cdot 1 \cdot 178 : 6 i

x_{1, 2} = \frac{- 26 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 26 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 26 - 6 i}{2 \cdot 1}

x = \frac{- 26 + 6 i}{2 \cdot 1} : - 13 + 3 i

x = \frac{- 26 - 6 i}{2 \cdot 1} : - 13 - 3 i

The solutions to the quadratic equation are:

x = - 13 + 3 i, x = - 13 - 3 i

z^{2} + z^{2} = 9^{2}

6 x = 16 - x^{2}

(2 x - 7)^{2} = 81

0 = 5 x^{2} + 29 x - 6

6 x^{2} - 49 = 0

What are the solutions to the equation x^2+26x=-178 ?
The solutions to the equation x^2+26x=-178 are x=-13+3i,x=-13-3i
Find the zeros of x^2+26x=-178
The zeros of x^2+26x=-178 are x=-13+3i,x=-13-3i