What are the solutions to the equation 23u^2+40u=0 ?

The solutions to the equation 23u^2+40u=0 are u=0,u=-40/23

Find the zeros of 23u^2+40u=0

The zeros of 23u^2+40u=0 are u=0,u=-40/23

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23 u^{2} + 40 u = 0

u = 0, u = - \frac{40}{23}

Decimal Notation

u = 0, u = - 1.73913 \dots

Solution steps

23 u^{2} + 40 u = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 23 \cdot 0}{2 \cdot 23}

4 0^{2} - 4 \cdot 23 \cdot 0 = 40

u_{1, 2} = \frac{- 40 \pm 40}{2 \cdot 23}

Separate the solutions

u_{1} = \frac{- 40 + 40}{2 \cdot 23}, u_{2} = \frac{- 40 - 40}{2 \cdot 23}

u = \frac{- 40 + 40}{2 \cdot 23} : 0

u = \frac{- 40 - 40}{2 \cdot 23} : - \frac{40}{23}

The solutions to the quadratic equation are:

u = 0, u = - \frac{40}{23}

x^{2} - 6 x + 4 = 0

2 x^{2} + 3 = - 3

x^{2} + x - 3 = 0

117 x^{2} + 1 = 18 x

37.5 X^{2} = 16, 4 + \frac{0.72}{X}

What are the solutions to the equation 23u^2+40u=0 ?
The solutions to the equation 23u^2+40u=0 are u=0,u=-40/23
Find the zeros of 23u^2+40u=0
The zeros of 23u^2+40u=0 are u=0,u=-40/23