What are the solutions to the equation quadraticformula x^2-6x+4=0 ?

The solutions to the equation quadraticformula x^2-6x+4=0 are x=3+sqrt(5),x=3-sqrt(5)

Find the zeros of quadraticformula x^2-6x+4=0

The zeros of quadraticformula x^2-6x+4=0 are x=3+sqrt(5),x=3-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 6 x + 4 = 0

x = 3 + 5, x = 3 - 5

Decimal Notation

x = 5.23606 \dots, x = 0.76393 \dots

Solution steps

x^{2} - 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 4 = 25

x_{1, 2} = \frac{- ( - 6 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 5}{2 \cdot 1} : 3 + 5

x = \frac{- ( - 6 ) - 2 5}{2 \cdot 1} : 3 - 5

The solutions to the quadratic equation are:

x = 3 + 5, x = 3 - 5

2 x^{2} + 3 = - 3

x^{2} + x - 3 = 0

117 x^{2} + 1 = 18 x

37.5 X^{2} = 16, 4 + \frac{0.72}{X}

y, 0 = 0.05 y - 0.0005 y^{2}

What are the solutions to the equation quadraticformula x^2-6x+4=0 ?
The solutions to the equation quadraticformula x^2-6x+4=0 are x=3+sqrt(5),x=3-sqrt(5)
Find the zeros of quadraticformula x^2-6x+4=0
The zeros of quadraticformula x^2-6x+4=0 are x=3+sqrt(5),x=3-sqrt(5)