What are the solutions to the equation completesquare x^2+x-3=0 ?

The solutions to the equation completesquare x^2+x-3=0 are x=(sqrt(13)-1)/2 ,x=(-sqrt(13)-1)/2

Find the zeros of completesquare x^2+x-3=0

The zeros of completesquare x^2+x-3=0 are x=(sqrt(13)-1)/2 ,x=(-sqrt(13)-1)/2

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x^{2} + x - 3 = 0

x = \frac{13 - 1}{2}, x = \frac{- 13 - 1}{2}

Decimal Notation

x = 1.30277 \dots, x = - 2.30277 \dots

Solution steps

x^{2} + x - 3 = 0

Move

3

to the right side

x^{2} + x = 3

Rewrite in the form

(x + a)^{2} = b

(x + \frac{1}{2})^{2} = \frac{13}{4}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{1}{2} = \frac{13}{4} : x = \frac{13 - 1}{2}

Solve

x + \frac{1}{2} = - \frac{13}{4} : x = \frac{- 13 - 1}{2}

The solutions to the quadratic equation are:

x = \frac{13 - 1}{2}, x = \frac{- 13 - 1}{2}

117 x^{2} + 1 = 18 x

37.5 X^{2} = 16, 4 + \frac{0.72}{X}

y, 0 = 0.05 y - 0.0005 y^{2}

(x + 3) (x + 4) = 7 (x + 2)

x^{2} - 300 x - 22500 = 0

What are the solutions to the equation completesquare x^2+x-3=0 ?
The solutions to the equation completesquare x^2+x-3=0 are x=(sqrt(13)-1)/2 ,x=(-sqrt(13)-1)/2
Find the zeros of completesquare x^2+x-3=0
The zeros of completesquare x^2+x-3=0 are x=(sqrt(13)-1)/2 ,x=(-sqrt(13)-1)/2