What are the solutions to the equation 2x^2+3=-3 ?

The solutions to the equation 2x^2+3=-3 are x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of 2x^2+3=-3

The zeros of 2x^2+3=-3 are x=sqrt(3)i,x=-sqrt(3)i

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2 x^{2} + 3 = - 3

x = 3 i, x = - 3 i

Solution steps

2 x^{2} + 3 = - 3

Move

3

to the right side

2 x^{2} = - 6

Divide both sides by

2

x^{2} = - 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 3, x = - - 3

- 3 = 3 i

- - 3 = - 3 i

x = 3 i, x = - 3 i

x^{2} + x - 3 = 0

117 x^{2} + 1 = 18 x

37.5 X^{2} = 16, 4 + \frac{0.72}{X}

y, 0 = 0.05 y - 0.0005 y^{2}

(x + 3) (x + 4) = 7 (x + 2)

What are the solutions to the equation 2x^2+3=-3 ?
The solutions to the equation 2x^2+3=-3 are x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of 2x^2+3=-3
The zeros of 2x^2+3=-3 are x=sqrt(3)i,x=-sqrt(3)i