What are the solutions to the equation (x+3)(x+4)=7(x+2) ?

The solutions to the equation (x+3)(x+4)=7(x+2) are x=sqrt(2),x=-sqrt(2)

Find the zeros of (x+3)(x+4)=7(x+2)

The zeros of (x+3)(x+4)=7(x+2) are x=sqrt(2),x=-sqrt(2)

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(x + 3) (x + 4) = 7 (x + 2)

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

(x + 3) (x + 4) = 7 (x + 2)

Expand

(x + 3) (x + 4) : x^{2} + 7 x + 12

Expand

7 (x + 2) : 7 x + 14

x^{2} + 7 x + 12 = 7 x + 14

Move

12

to the right side

x^{2} + 7 x = 7 x + 2

Move

7 x

to the left side

x^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 2, x = - 2

x^{2} - 300 x - 22500 = 0

6 x^{2} - 8 x - 7 = 0

y = x^{2} - 5 x + 6, x

x, f (x + 5) = x^{2} + 2 x + 3

(2 x - 1) (2 x + 1) = (2 x - 3) 2

What are the solutions to the equation (x+3)(x+4)=7(x+2) ?
The solutions to the equation (x+3)(x+4)=7(x+2) are x=sqrt(2),x=-sqrt(2)
Find the zeros of (x+3)(x+4)=7(x+2)
The zeros of (x+3)(x+4)=7(x+2) are x=sqrt(2),x=-sqrt(2)