What are the solutions to the equation 4(x+7)^2=36 ?

The solutions to the equation 4(x+7)^2=36 are x=-4,x=-10

Find the zeros of 4(x+7)^2=36

The zeros of 4(x+7)^2=36 are x=-4,x=-10

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4 (x + 7)^{2} = 36

x = - 4, x = - 10

Solution steps

4 (x + 7)^{2} = 36

Divide both sides by

4

(x + 7)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 9 : x = - 4

Solve

x + 7 = - 9 : x = - 10

The solutions to the quadratic equation are:

x = - 4, x = - 10

x^{2} + (73)^{2} = (2 x)^{2}

y^{2} + 10 y + 35 = 0

6 x^{2} = 4 - 8 x

x, x^{2} - x = 12

2 ab x^{2} - (b^{2} + 6 a^{2}) x + 3 ab = 0

What are the solutions to the equation 4(x+7)^2=36 ?
The solutions to the equation 4(x+7)^2=36 are x=-4,x=-10
Find the zeros of 4(x+7)^2=36
The zeros of 4(x+7)^2=36 are x=-4,x=-10