What are the solutions to the equation 4w^2+12w=-9 ?

The solutions to the equation 4w^2+12w=-9 are w=-3/2

Find the zeros of 4w^2+12w=-9

The zeros of 4w^2+12w=-9 are w=-3/2

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4 w^{2} + 12 w = - 9

w = - \frac{3}{2}

Decimal Notation

w = - 1.5

Solution steps

4 w^{2} + 12 w = - 9

Move

9

to the left side

4 w^{2} + 12 w + 9 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 \cdot 9 = 0

w_{1, 2} = \frac{- 12 \pm 0}{2 \cdot 4}

w = \frac{- 12}{2 \cdot 4}

\frac{- 12}{2 \cdot 4} = - \frac{3}{2}

w = - \frac{3}{2}

The solution to the quadratic equation is:

w = - \frac{3}{2}

- 0.2 x^{2} + 3 x + 0.25 = 0

- 110 = 10 - 5 x^{2}

x^{2} + 13 x + 27 = 0

- 2^{2} + 3^{2} = c^{2}

4 x^{2} + 4 x + 65

What are the solutions to the equation 4w^2+12w=-9 ?
The solutions to the equation 4w^2+12w=-9 are w=-3/2
Find the zeros of 4w^2+12w=-9
The zeros of 4w^2+12w=-9 are w=-3/2