What are the solutions to the equation x^2+13x+27=0 ?

The solutions to the equation x^2+13x+27=0 are x=(-13+sqrt(61))/2 ,x=(-13-sqrt(61))/2

Find the zeros of x^2+13x+27=0

The zeros of x^2+13x+27=0 are x=(-13+sqrt(61))/2 ,x=(-13-sqrt(61))/2

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x^{2} + 13 x + 27 = 0

x = \frac{- 13 + 61}{2}, x = \frac{- 13 - 61}{2}

Decimal Notation

x = - 2.59487 \dots, x = - 10.40512 \dots

Solution steps

x^{2} + 13 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 27}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 27 = 61

x_{1, 2} = \frac{- 13 \pm 61}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 61}{2 \cdot 1}, x_{2} = \frac{- 13 - 61}{2 \cdot 1}

x = \frac{- 13 + 61}{2 \cdot 1} : \frac{- 13 + 61}{2}

x = \frac{- 13 - 61}{2 \cdot 1} : \frac{- 13 - 61}{2}

The solutions to the quadratic equation are:

x = \frac{- 13 + 61}{2}, x = \frac{- 13 - 61}{2}

- 2^{2} + 3^{2} = c^{2}

4 x^{2} + 4 x + 65

y, 4 y^{2} + 18 = 96 x

2 q^{2} + 9 = - q

(x + 3) (x + 7) = 11

What are the solutions to the equation x^2+13x+27=0 ?
The solutions to the equation x^2+13x+27=0 are x=(-13+sqrt(61))/2 ,x=(-13-sqrt(61))/2
Find the zeros of x^2+13x+27=0
The zeros of x^2+13x+27=0 are x=(-13+sqrt(61))/2 ,x=(-13-sqrt(61))/2