What are the solutions to the equation (x+9)^2+8(x+9)+12=0 ?

The solutions to the equation (x+9)^2+8(x+9)+12=0 are x=-11,x=-15

Find the zeros of (x+9)^2+8(x+9)+12=0

The zeros of (x+9)^2+8(x+9)+12=0 are x=-11,x=-15

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(x + 9)^{2} + 8 (x + 9) + 12 = 0

x = - 11, x = - 15

Solution steps

(x + 9)^{2} + 8 (x + 9) + 12 = 0

Expand

(x + 9)^{2} + 8 (x + 9) + 12 : x^{2} + 26 x + 165

x^{2} + 26 x + 165 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 1 \cdot 165}{2 \cdot 1}

2 6^{2} - 4 \cdot 1 \cdot 165 = 4

x_{1, 2} = \frac{- 26 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 26 + 4}{2 \cdot 1}, x_{2} = \frac{- 26 - 4}{2 \cdot 1}

x = \frac{- 26 + 4}{2 \cdot 1} : - 11

x = \frac{- 26 - 4}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = - 11, x = - 15

- 3 x^{2} - 10 x + 24 = 0

3 x^{2} = 1200

1 - 3 x + 2 x^{2} = 0

3 x^{2} + 2 x - 2 - 3 = 0

- 2 y^{2} - 5 y + 6 = 0

What are the solutions to the equation (x+9)^2+8(x+9)+12=0 ?
The solutions to the equation (x+9)^2+8(x+9)+12=0 are x=-11,x=-15
Find the zeros of (x+9)^2+8(x+9)+12=0
The zeros of (x+9)^2+8(x+9)+12=0 are x=-11,x=-15