What are the solutions to the equation -3x^2-10x+24=0 ?

The solutions to the equation -3x^2-10x+24=0 are x=-(5+sqrt(97))/3 ,x=(sqrt(97)-5)/3

Find the zeros of -3x^2-10x+24=0

The zeros of -3x^2-10x+24=0 are x=-(5+sqrt(97))/3 ,x=(sqrt(97)-5)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} - 10 x + 24 = 0

x = - \frac{5 + 97}{3}, x = \frac{97 - 5}{3}

Decimal Notation

x = - 4.94961 \dots, x = 1.61628 \dots

Solution steps

- 3 x^{2} - 10 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 3 ) \cdot 24}{2 ( - 3 )}

(- 10)^{2} - 4 (- 3) \cdot 24 = 297

x_{1, 2} = \frac{- ( - 10 ) \pm 2 97}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 97}{2 ( - 3 )}, x_{2} = \frac{- ( - 10 ) - 2 97}{2 ( - 3 )}

x = \frac{- ( - 10 ) + 2 97}{2 ( - 3 )} : - \frac{5 + 97}{3}

x = \frac{- ( - 10 ) - 2 97}{2 ( - 3 )} : \frac{97 - 5}{3}

The solutions to the quadratic equation are:

x = - \frac{5 + 97}{3}, x = \frac{97 - 5}{3}

3 x^{2} = 1200

1 - 3 x + 2 x^{2} = 0

3 x^{2} + 2 x - 2 - 3 = 0

- 2 y^{2} - 5 y + 6 = 0

3 s^{2} + 0.5 s + 2 = 0

What are the solutions to the equation -3x^2-10x+24=0 ?
The solutions to the equation -3x^2-10x+24=0 are x=-(5+sqrt(97))/3 ,x=(sqrt(97)-5)/3
Find the zeros of -3x^2-10x+24=0
The zeros of -3x^2-10x+24=0 are x=-(5+sqrt(97))/3 ,x=(sqrt(97)-5)/3