What are the solutions to the equation factor 12-4x-x^2=0 ?

The solutions to the equation factor 12-4x-x^2=0 are x=2,x=-6

Find the zeros of factor 12-4x-x^2=0

The zeros of factor 12-4x-x^2=0 are x=2,x=-6

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12 - 4 x - x^{2} = 0

x = 2, x = - 6

Solution steps

12 - 4 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} - 4 x + 12 = 0

Factor

- x^{2} - 4 x + 12 : - (x - 2) (x + 6)

- (x - 2) (x + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 6 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 6 = 0 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

(x + 7) (x - 7) = - 7

y^{2} - 4 y = 12

30.7886 X^{2} + 68.4915 X - 60 = 0

x (x - 12) = 38

w^{2} = 3 (w - 2)

What are the solutions to the equation factor 12-4x-x^2=0 ?
The solutions to the equation factor 12-4x-x^2=0 are x=2,x=-6
Find the zeros of factor 12-4x-x^2=0
The zeros of factor 12-4x-x^2=0 are x=2,x=-6