What are the solutions to the equation solvefor s,r=ts^2+3 ?

The solutions to the equation solvefor s,r=ts^2+3 are s=sqrt((r-3)/t),s=-sqrt((r-3)/t);\quad t\ne 0

Find the zeros of solvefor s,r=ts^2+3

The zeros of solvefor s,r=ts^2+3 are s=sqrt((r-3)/t),s=-sqrt((r-3)/t);\quad t\ne 0

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solve for

s, r = t s^{2} + 3

s = \frac{r - 3}{t}, s = - \frac{r - 3}{t}; t \neq = 0

Solution steps

r = t s^{2} + 3

Switch sides

t s^{2} + 3 = r

Move

3

to the right side

t s^{2} = r - 3

Divide both sides by

t; t \neq = 0

s^{2} = \frac{r - 3}{t}; t \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = \frac{r - 3}{t}, s = - \frac{r - 3}{t}; t \neq = 0

- 6 x^{2} - 12 x + 48 = 0

1 - 0.8 x - 0.16 x^{2} = 0

12 x^{2} + 8 x = 20

a^{2} + 4 0^{2} = 4 1^{2}

1 4^{2} + 2 0^{2} = c^{2}

What are the solutions to the equation solvefor s,r=ts^2+3 ?
The solutions to the equation solvefor s,r=ts^2+3 are s=sqrt((r-3)/t),s=-sqrt((r-3)/t);\quad t\ne 0
Find the zeros of solvefor s,r=ts^2+3
The zeros of solvefor s,r=ts^2+3 are s=sqrt((r-3)/t),s=-sqrt((r-3)/t);\quad t\ne 0