What are the solutions to the equation -6x^2-12x+48=0 ?

The solutions to the equation -6x^2-12x+48=0 are x=-4,x=2

Find the zeros of -6x^2-12x+48=0

The zeros of -6x^2-12x+48=0 are x=-4,x=2

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- 6 x^{2} - 12 x + 48 = 0

x = - 4, x = 2

Solution steps

- 6 x^{2} - 12 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 6 ) \cdot 48}{2 ( - 6 )}

(- 12)^{2} - 4 (- 6) \cdot 48 = 36

x_{1, 2} = \frac{- ( - 12 ) \pm 36}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 36}{2 ( - 6 )}, x_{2} = \frac{- ( - 12 ) - 36}{2 ( - 6 )}

x = \frac{- ( - 12 ) + 36}{2 ( - 6 )} : - 4

x = \frac{- ( - 12 ) - 36}{2 ( - 6 )} : 2

The solutions to the quadratic equation are:

x = - 4, x = 2

1 - 0.8 x - 0.16 x^{2} = 0

12 x^{2} + 8 x = 20

a^{2} + 4 0^{2} = 4 1^{2}

1 4^{2} + 2 0^{2} = c^{2}

x^{2} + 12 x + 400 = 0

What are the solutions to the equation -6x^2-12x+48=0 ?
The solutions to the equation -6x^2-12x+48=0 are x=-4,x=2
Find the zeros of -6x^2-12x+48=0
The zeros of -6x^2-12x+48=0 are x=-4,x=2