What are the solutions to the equation 10=(t^2-t)/2 ?

The solutions to the equation 10=(t^2-t)/2 are t=5,t=-4

Find the zeros of 10=(t^2-t)/2

The zeros of 10=(t^2-t)/2 are t=5,t=-4

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10 = \frac{t ^{2} - t}{2}

t = 5, t = - 4

Solution steps

10 = \frac{t ^{2} - t}{2}

Multiply both sides by

2

20 = t^{2} - t

Switch sides

t^{2} - t = 20

Move

20

to the left side

t^{2} - t - 20 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

t_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, t_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

t = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

t = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

t = 5, t = - 4

4 x^{2} - 49 x = 12

x^{2} - 5 x + 8 = 0

2 x^{2} + 20 x = - 58

(x + 3)^{2} - 1 = 5

(2 x - 3)^{2} - 5 = 5

What are the solutions to the equation 10=(t^2-t)/2 ?
The solutions to the equation 10=(t^2-t)/2 are t=5,t=-4
Find the zeros of 10=(t^2-t)/2
The zeros of 10=(t^2-t)/2 are t=5,t=-4