What are the solutions to the equation completesquare x^2-5x+8=0 ?

The solutions to the equation completesquare x^2-5x+8=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2

Find the zeros of completesquare x^2-5x+8=0

The zeros of completesquare x^2-5x+8=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2

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x^{2} - 5 x + 8 = 0

x = \frac{5}{2} + i \frac{7}{2}, x = \frac{5}{2} - i \frac{7}{2}

Solution steps

x^{2} - 5 x + 8 = 0

Move

8

to the right side

x^{2} - 5 x = - 8

Rewrite in the form

(x + a)^{2} = b

(x - \frac{5}{2})^{2} = - \frac{7}{4}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{5}{2} = - \frac{7}{4} : x = \frac{5}{2} + i \frac{7}{2}

Solve

x - \frac{5}{2} = - - \frac{7}{4} : x = \frac{5}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{7}{2}, x = \frac{5}{2} - i \frac{7}{2}

2 x^{2} + 20 x = - 58

(x + 3)^{2} - 1 = 5

(2 x - 3)^{2} - 5 = 5

(2 x - 3)^{2} - 5 = 4

4 x^{2} + 13 x = - 3

What are the solutions to the equation completesquare x^2-5x+8=0 ?
The solutions to the equation completesquare x^2-5x+8=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2
Find the zeros of completesquare x^2-5x+8=0
The zeros of completesquare x^2-5x+8=0 are x= 5/2+i(sqrt(7))/2 ,x= 5/2-i(sqrt(7))/2