What are the solutions to the equation (x+3)^2-1=5 ?

The solutions to the equation (x+3)^2-1=5 are x=sqrt(6)-3,x=-sqrt(6)-3

Find the zeros of (x+3)^2-1=5

The zeros of (x+3)^2-1=5 are x=sqrt(6)-3,x=-sqrt(6)-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 3)^{2} - 1 = 5

x = 6 - 3, x = - 6 - 3

Decimal Notation

x = - 0.55051 \dots, x = - 5.44948 \dots

Solution steps

(x + 3)^{2} - 1 = 5

Move

1

to the right side

(x + 3)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 6 : x = 6 - 3

Solve

x + 3 = - 6 : x = - 6 - 3

The solutions to the quadratic equation are:

x = 6 - 3, x = - 6 - 3

(2 x - 3)^{2} - 5 = 5

(2 x - 3)^{2} - 5 = 4

4 x^{2} + 13 x = - 3

2 n^{2} - 8 n = 3

50 = 20 (t) + 0.5 (9.8) \cdot t^{2}

What are the solutions to the equation (x+3)^2-1=5 ?
The solutions to the equation (x+3)^2-1=5 are x=sqrt(6)-3,x=-sqrt(6)-3
Find the zeros of (x+3)^2-1=5
The zeros of (x+3)^2-1=5 are x=sqrt(6)-3,x=-sqrt(6)-3