What are the solutions to the equation x^2+2x+2=1 ?

The solutions to the equation x^2+2x+2=1 are x=-1

Find the zeros of x^2+2x+2=1

The zeros of x^2+2x+2=1 are x=-1

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x^{2} + 2 x + 2 = 1

x = - 1

Solution steps

x^{2} + 2 x + 2 = 1

Move

1

to the left side

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

3 x^{2} - 12 = - 6 x

0 = 30 + 12 t + \frac{- 9.8 t ^{2}}{2}

(8 x - 13) (10 x + 19) = 0

x^{2} - 20 x = - 89

q^{2} - 8 = 17

What are the solutions to the equation x^2+2x+2=1 ?
The solutions to the equation x^2+2x+2=1 are x=-1
Find the zeros of x^2+2x+2=1
The zeros of x^2+2x+2=1 are x=-1