What are the solutions to the equation 3x^2-12=-6x ?

The solutions to the equation 3x^2-12=-6x are x=-1+sqrt(5),x=-1-sqrt(5)

Find the zeros of 3x^2-12=-6x

The zeros of 3x^2-12=-6x are x=-1+sqrt(5),x=-1-sqrt(5)

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3 x^{2} - 12 = - 6 x

x = - 1 + 5, x = - 1 - 5

Decimal Notation

x = 1.23606 \dots, x = - 3.23606 \dots

Solution steps

3 x^{2} - 12 = - 6 x

Move

6 x

to the left side

3 x^{2} - 12 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 12) = 65

x_{1, 2} = \frac{- 6 \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6 5}{2 \cdot 3}, x_{2} = \frac{- 6 - 6 5}{2 \cdot 3}

x = \frac{- 6 + 6 5}{2 \cdot 3} : - 1 + 5

x = \frac{- 6 - 6 5}{2 \cdot 3} : - 1 - 5

The solutions to the quadratic equation are:

x = - 1 + 5, x = - 1 - 5

0 = 30 + 12 t + \frac{- 9.8 t ^{2}}{2}

(8 x - 13) (10 x + 19) = 0

x^{2} - 20 x = - 89

q^{2} - 8 = 17

x^{1} - x^{2} = 0, 3 x^{1} - 2 x^{2} = - 1

What are the solutions to the equation 3x^2-12=-6x ?
The solutions to the equation 3x^2-12=-6x are x=-1+sqrt(5),x=-1-sqrt(5)
Find the zeros of 3x^2-12=-6x
The zeros of 3x^2-12=-6x are x=-1+sqrt(5),x=-1-sqrt(5)