What are the solutions to the equation 4t=t^2 ?

The solutions to the equation 4t=t^2 are t=4,t=0

Find the zeros of 4t=t^2

The zeros of 4t=t^2 are t=4,t=0

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4 t = t^{2}

t = 4, t = 0

Solution steps

4 t = t^{2}

Switch sides

t^{2} = 4 t

Move

4 t

to the left side

t^{2} - 4 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

t_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, t_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

t = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

t = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 4, t = 0

k^{2} - 9 k + 20 = 0

x^{2} - 2.455 x + 1.25 = 0

3 x (x + 2) - 5 (x - 3) = 17

3 x^{2} - 22 x = 16

x^{2} + (3 + x)^{2} = (6 + x)^{2}

What are the solutions to the equation 4t=t^2 ?
The solutions to the equation 4t=t^2 are t=4,t=0
Find the zeros of 4t=t^2
The zeros of 4t=t^2 are t=4,t=0