What are the solutions to the equation 4a^2=-16 ?

The solutions to the equation 4a^2=-16 are a=2i,a=-2i

Find the zeros of 4a^2=-16

The zeros of 4a^2=-16 are a=2i,a=-2i

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4 a^{2} = - 16

a = 2 i, a = - 2 i

Solution steps

4 a^{2} = - 16

Divide both sides by

4

a^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = - 4, a = - - 4

- 4 = 2 i

- - 4 = - 2 i

a = 2 i, a = - 2 i

4 = 3 x^{2} - x

d^{2} + d - 19 = 4 d

m^{2} + 11 m = - 30

x^{(2)} + 5 x + 6 = 0

x, f (a + h) = - 5 x^{2} + 2 x - 1

What are the solutions to the equation 4a^2=-16 ?
The solutions to the equation 4a^2=-16 are a=2i,a=-2i
Find the zeros of 4a^2=-16
The zeros of 4a^2=-16 are a=2i,a=-2i