What are the solutions to the equation 7x^2-1=5x ?

The solutions to the equation 7x^2-1=5x are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)

Find the zeros of 7x^2-1=5x

The zeros of 7x^2-1=5x are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 x^{2} - 1 = 5 x

x = \frac{5 + 53}{14}, x = \frac{5 - 53}{14}

Decimal Notation

x = 0.87715 \dots, x = - 0.16286 \dots

Solution steps

7 x^{2} - 1 = 5 x

Move

5 x

to the left side

7 x^{2} - 1 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} - 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 7 ( - 1 )}{2 \cdot 7}

(- 5)^{2} - 4 \cdot 7 (- 1) = 53

x_{1, 2} = \frac{- ( - 5 ) \pm 53}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 53}{2 \cdot 7}, x_{2} = \frac{- ( - 5 ) - 53}{2 \cdot 7}

x = \frac{- ( - 5 ) + 53}{2 \cdot 7} : \frac{5 + 53}{14}

x = \frac{- ( - 5 ) - 53}{2 \cdot 7} : \frac{5 - 53}{14}

The solutions to the quadratic equation are:

x = \frac{5 + 53}{14}, x = \frac{5 - 53}{14}

(a + 1) 3 (a - 1) = 8^{\circ}

- 2 x^{2} + 8 x + 9 = 0

4 x^{2} - 14 x + 49 = 0

16 = \frac{4}{3} (8 x + 3) 34 (8 x + 3)

x^{2} = 3 (x + 6)

What are the solutions to the equation 7x^2-1=5x ?
The solutions to the equation 7x^2-1=5x are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)
Find the zeros of 7x^2-1=5x
The zeros of 7x^2-1=5x are x=(5+sqrt(53))/(14),x=(5-sqrt(53))/(14)