What are the solutions to the equation 3(x-5)^2-27=0 ?

The solutions to the equation 3(x-5)^2-27=0 are x=8,x=2

Find the zeros of 3(x-5)^2-27=0

The zeros of 3(x-5)^2-27=0 are x=8,x=2

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3 (x - 5)^{2} - 27 = 0

x = 8, x = 2

Solution steps

3 (x - 5)^{2} - 27 = 0

Move

27

to the right side

3 (x - 5)^{2} = 27

Divide both sides by

3

(x - 5)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 9 : x = 8

Solve

x - 5 = - 9 : x = 2

The solutions to the quadratic equation are:

x = 8, x = 2

- x^{2} + 4 = x + 2

x^{2} + 6 x = 16

(2 - x)^{2} - 4 = 0

n^{2} - 11 n + 10 = 0

x^{2} - 10 x + 9 = 0

What are the solutions to the equation 3(x-5)^2-27=0 ?
The solutions to the equation 3(x-5)^2-27=0 are x=8,x=2
Find the zeros of 3(x-5)^2-27=0
The zeros of 3(x-5)^2-27=0 are x=8,x=2