What are the solutions to the equation (2-x)^2-4=0 ?

The solutions to the equation (2-x)^2-4=0 are x=0,x=4

Find the zeros of (2-x)^2-4=0

The zeros of (2-x)^2-4=0 are x=0,x=4

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(2 - x)^{2} - 4 = 0

x = 0, x = 4

Solution steps

(2 - x)^{2} - 4 = 0

Move

4

to the right side

(2 - x)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 - x = 4 : x = 0

Solve

2 - x = - 4 : x = 4

The solutions to the quadratic equation are:

x = 0, x = 4

n^{2} - 11 n + 10 = 0

x^{2} - 10 x + 9 = 0

(x + 3)^{2} = 3 x (5 x - 1) - 3 (x - 2)

(3 x - 8) (6 x - 1) = 3

2 a^{2} = x^{2}

What are the solutions to the equation (2-x)^2-4=0 ?
The solutions to the equation (2-x)^2-4=0 are x=0,x=4
Find the zeros of (2-x)^2-4=0
The zeros of (2-x)^2-4=0 are x=0,x=4