What are the solutions to the equation 3x^2+2=3x ?

The solutions to the equation 3x^2+2=3x are x= 1/2+i(sqrt(15))/6 ,x= 1/2-i(sqrt(15))/6

Find the zeros of 3x^2+2=3x

The zeros of 3x^2+2=3x are x= 1/2+i(sqrt(15))/6 ,x= 1/2-i(sqrt(15))/6

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3 x^{2} + 2 = 3 x

x = \frac{1}{2} + i \frac{15}{6}, x = \frac{1}{2} - i \frac{15}{6}

Solution steps

3 x^{2} + 2 = 3 x

Move

3 x

to the left side

3 x^{2} + 2 - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

(- 3)^{2} - 4 \cdot 3 \cdot 2 : 15 i

x_{1, 2} = \frac{- ( - 3 ) \pm 15 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 15 i}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 15 i}{2 \cdot 3}

x = \frac{- ( - 3 ) + 15 i}{2 \cdot 3} : \frac{1}{2} + i \frac{15}{6}

x = \frac{- ( - 3 ) - 15 i}{2 \cdot 3} : \frac{1}{2} - i \frac{15}{6}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{15}{6}, x = \frac{1}{2} - i \frac{15}{6}

π x^{2} + 13 x + 1 = 0

2 (x + 1)^{2} = 3

15 = 7 + 23 t - 16 t^{2}

x^{2} + 10 x - 8 = 0

y^{2} - 6 a y + (9 a^{2} - 4) = 0

What are the solutions to the equation 3x^2+2=3x ?
The solutions to the equation 3x^2+2=3x are x= 1/2+i(sqrt(15))/6 ,x= 1/2-i(sqrt(15))/6
Find the zeros of 3x^2+2=3x
The zeros of 3x^2+2=3x are x= 1/2+i(sqrt(15))/6 ,x= 1/2-i(sqrt(15))/6