What are the solutions to the equation 40+3x-5x^2=0 ?

The solutions to the equation 40+3x-5x^2=0 are x=-(-3+sqrt(809))/(10),x=(3+sqrt(809))/(10)

Find the zeros of 40+3x-5x^2=0

The zeros of 40+3x-5x^2=0 are x=-(-3+sqrt(809))/(10),x=(3+sqrt(809))/(10)

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40 + 3 x - 5 x^{2} = 0

x = - \frac{- 3 + 809}{10}, x = \frac{3 + 809}{10}

Decimal Notation

x = - 2.54429 \dots, x = 3.14429 \dots

Solution steps

40 + 3 x - 5 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} + 3 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 5 ) \cdot 40}{2 ( - 5 )}

3^{2} - 4 (- 5) \cdot 40 = 809

x_{1, 2} = \frac{- 3 \pm 809}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 3 + 809}{2 ( - 5 )}, x_{2} = \frac{- 3 - 809}{2 ( - 5 )}

x = \frac{- 3 + 809}{2 ( - 5 )} : - \frac{- 3 + 809}{10}

x = \frac{- 3 - 809}{2 ( - 5 )} : \frac{3 + 809}{10}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 809}{10}, x = \frac{3 + 809}{10}

0.8 x^{2} + 0.8 x - 5 = 0

c^{2} + c - 7 = 0

x^{2} - 3 = x - 1

1 = (x - 1)^{2}

0.085 x^{2} - 5 x + 40 = 0

What are the solutions to the equation 40+3x-5x^2=0 ?
The solutions to the equation 40+3x-5x^2=0 are x=-(-3+sqrt(809))/(10),x=(3+sqrt(809))/(10)
Find the zeros of 40+3x-5x^2=0
The zeros of 40+3x-5x^2=0 are x=-(-3+sqrt(809))/(10),x=(3+sqrt(809))/(10)