What are the solutions to the equation x^2-9x-29=0 ?

The solutions to the equation x^2-9x-29=0 are x=(9+sqrt(197))/2 ,x=(9-sqrt(197))/2

Find the zeros of x^2-9x-29=0

The zeros of x^2-9x-29=0 are x=(9+sqrt(197))/2 ,x=(9-sqrt(197))/2

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x^{2} - 9 x - 29 = 0

x = \frac{9 + 197}{2}, x = \frac{9 - 197}{2}

Decimal Notation

x = 11.51783 \dots, x = - 2.51783 \dots

Solution steps

x^{2} - 9 x - 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 29 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 29) = 197

x_{1, 2} = \frac{- ( - 9 ) \pm 197}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 197}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 197}{2 \cdot 1}

x = \frac{- ( - 9 ) + 197}{2 \cdot 1} : \frac{9 + 197}{2}

x = \frac{- ( - 9 ) - 197}{2 \cdot 1} : \frac{9 - 197}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 197}{2}, x = \frac{9 - 197}{2}

x, y = - x^{2} + 6 x - 8

k^{2} - 10 k + 9 = 0

2 (x + 1)^{2} = 5 - 2 x (11 x + 5)

3 x^{2} - 5 x + 2 = 0, 4 x^{2} + 3 x - 22 = 0

6 x^{2} + 7 x - 3 = 0

What are the solutions to the equation x^2-9x-29=0 ?
The solutions to the equation x^2-9x-29=0 are x=(9+sqrt(197))/2 ,x=(9-sqrt(197))/2
Find the zeros of x^2-9x-29=0
The zeros of x^2-9x-29=0 are x=(9+sqrt(197))/2 ,x=(9-sqrt(197))/2