What are the solutions to the equation completesquare-x^2+x+6 ?

The solutions to the equation completesquare-x^2+x+6 are -(x-1/2)^2+25/4

Find the zeros of completesquare-x^2+x+6

The zeros of completesquare-x^2+x+6 are -(x-1/2)^2+25/4

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complete the square

- x^{2} + x + 6

- (x - \frac{1}{2})^{2} + \frac{25}{4}

Solution steps

- x^{2} + x + 6

Write

- x^{2} + x + 6

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 1

- (x^{2} - x - 6)

2 a = - 1 : a = - \frac{1}{2}

Add and subtract

(- \frac{1}{2})^{2}

- (x^{2} - x - 6 + (- \frac{1}{2})^{2} - (- \frac{1}{2})^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 1 x + (- \frac{1}{2})^{2} = (x - \frac{1}{2})^{2}

- ((x - \frac{1}{2})^{2} - 6 - (- \frac{1}{2})^{2})

Simplify

- (x - \frac{1}{2})^{2} + \frac{25}{4}

0 = y^{2} - 65

2 x^{2} - 8 x + 1 = 0

- 2 y^{2} = 9

46 x + 7 x^{2} = 21

3.14 \cdot x^{2} = 4

What are the solutions to the equation completesquare-x^2+x+6 ?
The solutions to the equation completesquare-x^2+x+6 are -(x-1/2)^2+25/4
Find the zeros of completesquare-x^2+x+6
The zeros of completesquare-x^2+x+6 are -(x-1/2)^2+25/4