What are the solutions to the equation 5u^2+7u=-2 ?

The solutions to the equation 5u^2+7u=-2 are u=-2/5 ,u=-1

Find the zeros of 5u^2+7u=-2

The zeros of 5u^2+7u=-2 are u=-2/5 ,u=-1

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5 u^{2} + 7 u = - 2

u = - \frac{2}{5}, u = - 1

Decimal Notation

u = - 0.4, u = - 1

Solution steps

5 u^{2} + 7 u = - 2

Move

2

to the left side

5 u^{2} + 7 u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

7^{2} - 4 \cdot 5 \cdot 2 = 3

u_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 5}

Separate the solutions

u_{1} = \frac{- 7 + 3}{2 \cdot 5}, u_{2} = \frac{- 7 - 3}{2 \cdot 5}

u = \frac{- 7 + 3}{2 \cdot 5} : - \frac{2}{5}

u = \frac{- 7 - 3}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

u = - \frac{2}{5}, u = - 1

(x - 5)^{2} - 8 = - 26

p^{2} + 2 p - 1 = 0

5 w^{2} - 9 w = 2

2 x^{2} - x 5 - 15 = 0

80 x + \frac{1}{2} (4) x^{2} - 1000 = 0

What are the solutions to the equation 5u^2+7u=-2 ?
The solutions to the equation 5u^2+7u=-2 are u=-2/5 ,u=-1
Find the zeros of 5u^2+7u=-2
The zeros of 5u^2+7u=-2 are u=-2/5 ,u=-1