What are the solutions to the equation (u)^2+u*2^2=3 ?

The solutions to the equation (u)^2+u*2^2=3 are u=-2+sqrt(7),u=-2-sqrt(7)

Find the zeros of (u)^2+u*2^2=3

The zeros of (u)^2+u*2^2=3 are u=-2+sqrt(7),u=-2-sqrt(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(u)^{2} + u \cdot 2^{2} = 3

u = - 2 + 7, u = - 2 - 7

Decimal Notation

u = 0.64575 \dots, u = - 4.64575 \dots

Solution steps

u^{2} + u \cdot 2^{2} = 3

Expand

u^{2} + u \cdot 2^{2} : u^{2} + 4 u

u^{2} + 4 u = 3

Move

3

to the left side

u^{2} + 4 u - 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 3) = 27

u_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 4 + 2 7}{2 \cdot 1}, u_{2} = \frac{- 4 - 2 7}{2 \cdot 1}

u = \frac{- 4 + 2 7}{2 \cdot 1} : - 2 + 7

u = \frac{- 4 - 2 7}{2 \cdot 1} : - 2 - 7

The solutions to the quadratic equation are:

u = - 2 + 7, u = - 2 - 7

4 u^{2} - 7 u - 2 = 0

- 4 (x - 1)^{2} + 28 = - 100

4 d^{2} + 9 = 12 d

2 p^{2} = 0

x^{2} - 20 x - 1500 = 0

What are the solutions to the equation (u)^2+u*2^2=3 ?
The solutions to the equation (u)^2+u*2^2=3 are u=-2+sqrt(7),u=-2-sqrt(7)
Find the zeros of (u)^2+u*2^2=3
The zeros of (u)^2+u*2^2=3 are u=-2+sqrt(7),u=-2-sqrt(7)