What are the solutions to the equation 4/6 =x^2 ?

The solutions to the equation 4/6 =x^2 are x=sqrt(2/3),x=-sqrt(2/3)

Find the zeros of 4/6 =x^2

The zeros of 4/6 =x^2 are x=sqrt(2/3),x=-sqrt(2/3)

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\frac{4}{6} = x^{2}

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 0.81649 \dots, x = - 0.81649 \dots

Solution steps

\frac{4}{6} = x^{2}

Switch sides

x^{2} = \frac{4}{6}

Cancel the common factor:

2

x^{2} = \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{3}, x = - \frac{2}{3}

(u)^{2} + u \cdot 2^{2} = 3

4 u^{2} - 7 u - 2 = 0

- 4 (x - 1)^{2} + 28 = - 100

4 d^{2} + 9 = 12 d

2 p^{2} = 0

What are the solutions to the equation 4/6 =x^2 ?
The solutions to the equation 4/6 =x^2 are x=sqrt(2/3),x=-sqrt(2/3)
Find the zeros of 4/6 =x^2
The zeros of 4/6 =x^2 are x=sqrt(2/3),x=-sqrt(2/3)