What are the solutions to the equation 4x^2-12x-280=0 ?

The solutions to the equation 4x^2-12x-280=0 are x=10,x=-7

Find the zeros of 4x^2-12x-280=0

The zeros of 4x^2-12x-280=0 are x=10,x=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 12 x - 280 = 0

x = 10, x = - 7

Solution steps

4 x^{2} - 12 x - 280 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 280 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 280) = 68

x_{1, 2} = \frac{- ( - 12 ) \pm 68}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 68}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 68}{2 \cdot 4}

x = \frac{- ( - 12 ) + 68}{2 \cdot 4} : 10

x = \frac{- ( - 12 ) - 68}{2 \cdot 4} : - 7

The solutions to the quadratic equation are:

x = 10, x = - 7

3 x^{2} + x - 4 = 0

8 x = 4 (x^{2} + 2 x)

x^{2} - 2 x + 82

- 3 x^{2} - 5 x = - 1

x, f (x + 1) = 3 x^{2} - x + 2

What are the solutions to the equation 4x^2-12x-280=0 ?
The solutions to the equation 4x^2-12x-280=0 are x=10,x=-7
Find the zeros of 4x^2-12x-280=0
The zeros of 4x^2-12x-280=0 are x=10,x=-7