What are the solutions to the equation 18=x^2+3x ?

The solutions to the equation 18=x^2+3x are x=3,x=-6

Find the zeros of 18=x^2+3x

The zeros of 18=x^2+3x are x=3,x=-6

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18 = x^{2} + 3 x

x = 3, x = - 6

Solution steps

18 = x^{2} + 3 x

Switch sides

x^{2} + 3 x = 18

Move

18

to the left side

x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 1}, x_{2} = \frac{- 3 - 9}{2 \cdot 1}

x = \frac{- 3 + 9}{2 \cdot 1} : 3

x = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

x, s (x) = 6 x^{2} + 3

x^{2} = 6 x - 13

x^{2} + x = 420

3 m^{2} - 4 = m

2 m^{2} + 13 m - 7 = 0

What are the solutions to the equation 18=x^2+3x ?
The solutions to the equation 18=x^2+3x are x=3,x=-6
Find the zeros of 18=x^2+3x
The zeros of 18=x^2+3x are x=3,x=-6