What are the solutions to the equation 4x^2-4x-120=0 ?

The solutions to the equation 4x^2-4x-120=0 are x=6,x=-5

Find the zeros of 4x^2-4x-120=0

The zeros of 4x^2-4x-120=0 are x=6,x=-5

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4 x^{2} - 4 x - 120 = 0

x = 6, x = - 5

Solution steps

4 x^{2} - 4 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 120 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 120) = 44

x_{1, 2} = \frac{- ( - 4 ) \pm 44}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 44}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 44}{2 \cdot 4}

x = \frac{- ( - 4 ) + 44}{2 \cdot 4} : 6

x = \frac{- ( - 4 ) - 44}{2 \cdot 4} : - 5

The solutions to the quadratic equation are:

x = 6, x = - 5

16 x + x^{2} = 14 + 13 x - x^{2}

5 a^{2} - 7 + 1 = 1.2

x^{2} - 6 + x = 0

x^{2} + 3 x = x

6 n^{2} + 12 n - 38 = 0

What are the solutions to the equation 4x^2-4x-120=0 ?
The solutions to the equation 4x^2-4x-120=0 are x=6,x=-5
Find the zeros of 4x^2-4x-120=0
The zeros of 4x^2-4x-120=0 are x=6,x=-5