What are the solutions to the equation 2(x+3)^2=9 ?

The solutions to the equation 2(x+3)^2=9 are x= 3/(sqrt(2))-3,x=-3/(sqrt(2))-3

Find the zeros of 2(x+3)^2=9

The zeros of 2(x+3)^2=9 are x= 3/(sqrt(2))-3,x=-3/(sqrt(2))-3

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2 (x + 3)^{2} = 9

x = \frac{3}{2} - 3, x = - \frac{3}{2} - 3

Decimal Notation

x = - 0.87867 \dots, x = - 5.12132 \dots

Solution steps

2 (x + 3)^{2} = 9

Divide both sides by

2

(x + 3)^{2} = \frac{9}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = \frac{9}{2} : x = \frac{3}{2} - 3

Solve

x + 3 = - \frac{9}{2} : x = - \frac{3}{2} - 3

The solutions to the quadratic equation are:

x = \frac{3}{2} - 3, x = - \frac{3}{2} - 3

4 r^{2} + 3 r + 6 = 357

144 x^{2} - 9 = 0

0 = x^{2} + 5 x - 14

x^{2} = 12 x - 32

y, s (y) = 5 yy + 7

What are the solutions to the equation 2(x+3)^2=9 ?
The solutions to the equation 2(x+3)^2=9 are x= 3/(sqrt(2))-3,x=-3/(sqrt(2))-3
Find the zeros of 2(x+3)^2=9
The zeros of 2(x+3)^2=9 are x= 3/(sqrt(2))-3,x=-3/(sqrt(2))-3