What are the solutions to the equation 2x^2-14x=21 ?

The solutions to the equation 2x^2-14x=21 are x=(7+sqrt(91))/2 ,x=(7-sqrt(91))/2

Find the zeros of 2x^2-14x=21

The zeros of 2x^2-14x=21 are x=(7+sqrt(91))/2 ,x=(7-sqrt(91))/2

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2 x^{2} - 14 x = 21

x = \frac{7 + 91}{2}, x = \frac{7 - 91}{2}

Decimal Notation

x = 8.26969 \dots, x = - 1.26969 \dots

Solution steps

2 x^{2} - 14 x = 21

Move

21

to the left side

2 x^{2} - 14 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

(- 14)^{2} - 4 \cdot 2 (- 21) = 291

x_{1, 2} = \frac{- ( - 14 ) \pm 2 91}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 91}{2 \cdot 2}, x_{2} = \frac{- ( - 14 ) - 2 91}{2 \cdot 2}

x = \frac{- ( - 14 ) + 2 91}{2 \cdot 2} : \frac{7 + 91}{2}

x = \frac{- ( - 14 ) - 2 91}{2 \cdot 2} : \frac{7 - 91}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 91}{2}, x = \frac{7 - 91}{2}

7 x^{2} + 8 x + 2 = 0

3 x^{2} - 12 = (x - 4)^{2} + 8 x

4 r (r - 3) - 3 (r - 3) = 0

x^{2} - 18 x - 32 = 0

k^{2} + 8 k + 12 = 0

What are the solutions to the equation 2x^2-14x=21 ?
The solutions to the equation 2x^2-14x=21 are x=(7+sqrt(91))/2 ,x=(7-sqrt(91))/2
Find the zeros of 2x^2-14x=21
The zeros of 2x^2-14x=21 are x=(7+sqrt(91))/2 ,x=(7-sqrt(91))/2