What are the solutions to the equation 7x^2+8x+2=0 ?

The solutions to the equation 7x^2+8x+2=0 are x=(-4+sqrt(2))/7 ,x=-(4+sqrt(2))/7

Find the zeros of 7x^2+8x+2=0

The zeros of 7x^2+8x+2=0 are x=(-4+sqrt(2))/7 ,x=-(4+sqrt(2))/7

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7 x^{2} + 8 x + 2 = 0

x = \frac{- 4 + 2}{7}, x = - \frac{4 + 2}{7}

Decimal Notation

x = - 0.36939 \dots, x = - 0.77345 \dots

Solution steps

7 x^{2} + 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 7 \cdot 2}{2 \cdot 7}

8^{2} - 4 \cdot 7 \cdot 2 = 22

x_{1, 2} = \frac{- 8 \pm 2 2}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 8 + 2 2}{2 \cdot 7}, x_{2} = \frac{- 8 - 2 2}{2 \cdot 7}

x = \frac{- 8 + 2 2}{2 \cdot 7} : \frac{- 4 + 2}{7}

x = \frac{- 8 - 2 2}{2 \cdot 7} : - \frac{4 + 2}{7}

The solutions to the quadratic equation are:

x = \frac{- 4 + 2}{7}, x = - \frac{4 + 2}{7}

3 x^{2} - 12 = (x - 4)^{2} + 8 x

4 r (r - 3) - 3 (r - 3) = 0

x^{2} - 18 x - 32 = 0

k^{2} + 8 k + 12 = 0

- 6 x + 5 x^{2} = - 8

What are the solutions to the equation 7x^2+8x+2=0 ?
The solutions to the equation 7x^2+8x+2=0 are x=(-4+sqrt(2))/7 ,x=-(4+sqrt(2))/7
Find the zeros of 7x^2+8x+2=0
The zeros of 7x^2+8x+2=0 are x=(-4+sqrt(2))/7 ,x=-(4+sqrt(2))/7