What are the solutions to the equation x^2-3abx=-3ab(x-3ab) ?

The solutions to the equation x^2-3abx=-3ab(x-3ab) are x=3ab,x=-3ab

Find the zeros of x^2-3abx=-3ab(x-3ab)

The zeros of x^2-3abx=-3ab(x-3ab) are x=3ab,x=-3ab

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x^{2} - 3 ab x = - 3 ab (x - 3 ab)

x = 3 ab, x = - 3 ab

Solution steps

x^{2} - 3 ab x = - 3 ab (x - 3 ab)

Expand

- 3 ab (x - 3 ab) : - 3 ab x + 9 a^{2} b^{2}

x^{2} - 3 ab x = - 3 ab x + 9 a^{2} b^{2}

Move

3 ab x

to the left side

x^{2} = 9 a^{2} b^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9 a^{2} b^{2}, x = - 9 a^{2} b^{2}

Simplify

9 a^{2} b^{2} : 3 ab

Simplify

- 9 a^{2} b^{2} : - 3 ab

x = 3 ab, x = - 3 ab

5 (x + 3)^{2} + 10 = 130

x^{2} = 6 x - 117

x^{2} - 3 x - 54 = 0

xx + 5 x = 24

- 10 x^{2} = 3 x^{2} - 3

What are the solutions to the equation x^2-3abx=-3ab(x-3ab) ?
The solutions to the equation x^2-3abx=-3ab(x-3ab) are x=3ab,x=-3ab
Find the zeros of x^2-3abx=-3ab(x-3ab)
The zeros of x^2-3abx=-3ab(x-3ab) are x=3ab,x=-3ab