What are the solutions to the equation b^2=3b ?

The solutions to the equation b^2=3b are b=3,b=0

Find the zeros of b^2=3b

The zeros of b^2=3b are b=3,b=0

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b^{2} = 3 b

b = 3, b = 0

Solution steps

b^{2} = 3 b

Move

3 b

to the left side

b^{2} - 3 b = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

b_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, b_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

b = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

b = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

b = 3, b = 0

3 k^{2} - 10 k - 25 = 0

3 x^{2} - 5 x + 1 = 0

14 x^{2} - 18 x + 36 = 0

2 w^{2} + 3 = - 7 w

x, x^{2} + 6 x - 27 = 0

What are the solutions to the equation b^2=3b ?
The solutions to the equation b^2=3b are b=3,b=0
Find the zeros of b^2=3b
The zeros of b^2=3b are b=3,b=0