What are the solutions to the equation 5x^2-7x+9=0 ?

The solutions to the equation 5x^2-7x+9=0 are x= 7/10+i(sqrt(131))/(10),x= 7/10-i(sqrt(131))/(10)

Find the zeros of 5x^2-7x+9=0

The zeros of 5x^2-7x+9=0 are x= 7/10+i(sqrt(131))/(10),x= 7/10-i(sqrt(131))/(10)

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5 x^{2} - 7 x + 9 = 0

x = \frac{7}{10} + i \frac{131}{10}, x = \frac{7}{10} - i \frac{131}{10}

Solution steps

5 x^{2} - 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 \cdot 9}{2 \cdot 5}

Simplify

(- 7)^{2} - 4 \cdot 5 \cdot 9 : 131 i

x_{1, 2} = \frac{- ( - 7 ) \pm 131 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 131 i}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 131 i}{2 \cdot 5}

x = \frac{- ( - 7 ) + 131 i}{2 \cdot 5} : \frac{7}{10} + i \frac{131}{10}

x = \frac{- ( - 7 ) - 131 i}{2 \cdot 5} : \frac{7}{10} - i \frac{131}{10}

The solutions to the quadratic equation are:

x = \frac{7}{10} + i \frac{131}{10}, x = \frac{7}{10} - i \frac{131}{10}

4 x^{2} + 10 x = 36

5 x - 0.56 x^{2} = 17

(x - 10) (x - 8) = - 1

2 x (x - 2) = 3

(x - 1)^{2} - 8 x - 8 - 9 = 0

What are the solutions to the equation 5x^2-7x+9=0 ?
The solutions to the equation 5x^2-7x+9=0 are x= 7/10+i(sqrt(131))/(10),x= 7/10-i(sqrt(131))/(10)
Find the zeros of 5x^2-7x+9=0
The zeros of 5x^2-7x+9=0 are x= 7/10+i(sqrt(131))/(10),x= 7/10-i(sqrt(131))/(10)