What are the solutions to the equation solvefor y^2+x=1,y ?

The solutions to the equation solvefor y^2+x=1,y are y=sqrt(1-x),y=-sqrt(1-x)

Find the zeros of solvefor y^2+x=1,y

The zeros of solvefor y^2+x=1,y are y=sqrt(1-x),y=-sqrt(1-x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

y^{2} + x = 1, y

y = 1 - x, y = - 1 - x

Solution steps

y^{2} + x = 1

Move

x

to the right side

y^{2} = 1 - x

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 1 - x, y = - 1 - x

y^{2} + 5 y - 1

x^{2} + 4 x = - 3

- 6 x^{2} + 3 x + 2 = 3

1 = 0.001 x^{2} - 0.612 x + 168

4 x^{2} = 40

What are the solutions to the equation solvefor y^2+x=1,y ?
The solutions to the equation solvefor y^2+x=1,y are y=sqrt(1-x),y=-sqrt(1-x)
Find the zeros of solvefor y^2+x=1,y
The zeros of solvefor y^2+x=1,y are y=sqrt(1-x),y=-sqrt(1-x)