What are the solutions to the equation 1x^2-2x=0 ?

The solutions to the equation 1x^2-2x=0 are x=2,x=0

Find the zeros of 1x^2-2x=0

The zeros of 1x^2-2x=0 are x=2,x=0

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1 x^{2} - 2 x = 0

x = 2, x = 0

Solution steps

1 \cdot x^{2} - 2 x = 0

Refine

x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

x = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 2, x = 0

4 x^{2} + 25 = 16 x

C = 3 x^{2} - 200 x + 5250.55

x^{2} - 18 x - 81 = - 161

x^{2} - 10 x + 7

4 d^{2} - d - 3 = - d^{2}

What are the solutions to the equation 1x^2-2x=0 ?
The solutions to the equation 1x^2-2x=0 are x=2,x=0
Find the zeros of 1x^2-2x=0
The zeros of 1x^2-2x=0 are x=2,x=0