What are the solutions to the equation 5p^2+11p+6=0 ?

The solutions to the equation 5p^2+11p+6=0 are p=-1,p=-6/5

Find the zeros of 5p^2+11p+6=0

The zeros of 5p^2+11p+6=0 are p=-1,p=-6/5

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5 p^{2} + 11 p + 6 = 0

p = - 1, p = - \frac{6}{5}

Decimal Notation

p = - 1, p = - 1.2

Solution steps

5 p^{2} + 11 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

1 1^{2} - 4 \cdot 5 \cdot 6 = 1

p_{1, 2} = \frac{- 11 \pm 1}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- 11 + 1}{2 \cdot 5}, p_{2} = \frac{- 11 - 1}{2 \cdot 5}

p = \frac{- 11 + 1}{2 \cdot 5} : - 1

p = \frac{- 11 - 1}{2 \cdot 5} : - \frac{6}{5}

The solutions to the quadratic equation are:

p = - 1, p = - \frac{6}{5}

(2 x + 4) (x - 3) = 0

7 x^{2} - x^{2} = 168

x^{2} + 10 x = 2

z^{2} + z - 6 = 0

(2 n - 1) v^{2} - 2 n v + 1 = 0

What are the solutions to the equation 5p^2+11p+6=0 ?
The solutions to the equation 5p^2+11p+6=0 are p=-1,p=-6/5
Find the zeros of 5p^2+11p+6=0
The zeros of 5p^2+11p+6=0 are p=-1,p=-6/5