What are the solutions to the equation 2y^2=-40 ?

The solutions to the equation 2y^2=-40 are y=2sqrt(5)i,y=-2sqrt(5)i

Find the zeros of 2y^2=-40

The zeros of 2y^2=-40 are y=2sqrt(5)i,y=-2sqrt(5)i

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2 y^{2} = - 40

y = 25 i, y = - 25 i

Solution steps

2 y^{2} = - 40

Divide both sides by

2

y^{2} = - 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 20, y = - - 20

- 20 = 25 i

- - 20 = - 25 i

y = 25 i, y = - 25 i

(x - 2) (2 x - 3) = 0

z^{2} + 0

5 x^{2} - 10 x = 6

9 x^{2} + 54 x + 79 = 0

- 4.9 x^{2} + 205.06 x + 210 = 0

What are the solutions to the equation 2y^2=-40 ?
The solutions to the equation 2y^2=-40 are y=2sqrt(5)i,y=-2sqrt(5)i
Find the zeros of 2y^2=-40
The zeros of 2y^2=-40 are y=2sqrt(5)i,y=-2sqrt(5)i