What are the solutions to the equation (k+4)^2=25 ?

The solutions to the equation (k+4)^2=25 are k=1,k=-9

Find the zeros of (k+4)^2=25

The zeros of (k+4)^2=25 are k=1,k=-9

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(k + 4)^{2} = 25

k = 1, k = - 9

Solution steps

(k + 4)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

k + 4 = 25 : k = 1

Solve

k + 4 = - 25 : k = - 9

The solutions to the quadratic equation are:

k = 1, k = - 9

x, f (x - 3) = x^{2} + 9 x + 5

104 = u^{2} - 5 u

(x - 2)^{2} + (x + 2)^{2} = 0

- x^{2} - 2 x + 19 = 0

x^{2} + 4 x + 64 = 0

What are the solutions to the equation (k+4)^2=25 ?
The solutions to the equation (k+4)^2=25 are k=1,k=-9
Find the zeros of (k+4)^2=25
The zeros of (k+4)^2=25 are k=1,k=-9